19m^2+5m-12=6m^2

Solution for 19m^2+5m-12=6m^2 equation:

19m^2+5m-12=6m^2

We move all terms to the left:

19m^2+5m-12-(6m^2)=0

determiningTheFunctionDomain
19m^2-6m^2+5m-12=0

We add all the numbers together, and all the variables

13m^2+5m-12=0

a = 13; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·13·(-12)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{649}}{2*13}=\frac{-5-\sqrt{649}}{26}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{649}}{2*13}=\frac{-5+\sqrt{649}}{26}
$